2x^2+(3(54/2))x=0

Solution for 2x^2+(3(54/2))x=0 equation:

2x^2+(3(54/2))x=0


Domain of the equation: 2))x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x^2+(327)x=0

We add all the numbers together, and all the variables

2x^2+327x=0

a = 2; b = 327; c = 0;
Δ = b2-4ac
Δ = 3272-4·2·0
Δ = 106929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{106929}=327$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(327)-327}{2*2}=\frac{-654}{4}
=-163+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(327)+327}{2*2}=\frac{0}{4}
=0
$